Lena K. answered • 07/11/19

Private Math Tutor

__Have:__

Point (6, -1) = (x, y)

Slope = -3

The proper linear equation is written in following form: y = mx + b (where m is slope, and b is y-intercept). Since we already have the slope, we need to find the y-intercept, b

So we plug in what we have:

y = mx + b

-1 = (-3)(6) + b, where we solve for b

-1 = -18 + b

b = 17

Finally, the equation of the line that passes through point (6, -1) and has a slope of -3 is **y = -3x + 17**