Why does cyclopropane react with bromine?

Question

In my exam, I was asked why cyclopropane could decolourise bromine water (indicating that it reacted with the bromine). All I could guess was that it is related to the high angle strain in cyclopropane, as the C–C–C bond angle is $60^\\circ$ instead of the required $109.5^\\circ$. No book I have read mentions this reaction. What is the product formed, and why does it occur?

Answer 1

Cyclopropane is an alkane and will react with bromine to undergo bromination via a free radical mechanism. This mechanism involves 3 steps: Initiation, propogating and terminating.

The product in this case would be bromocylcopropane.