How would you solve for this equation?

Question

4 x negative cubed y to the 0 power z to the fourth power over x to the -1 power y to the -1/3 power and z to the 6 power. -3/2

(4x^-3y^0z^4) / (x^-1y^-1/3 z^6) -3/2

Answer 1

gets rid of exponents less than or equal to zero; simplifies to:

4z^4/x^3 divided by (z^6/ (xy^(1/3))^(-3/2)

flips the second part over and multiplies each exponent by 3/2

4z^4/x^3 divided by (x^(3/2) y^(1/2) / z^9

KFC: keep, change, flip when dividing fractions:

4z^4/ x^3 * z^9 / x^(3/2)y^(1/2)

adds the exponents

4z^13 / x^(8/3)y^(1/2)