
Mark H. answered 07/01/19
Tutoring in Math and Science at all levels
OK--this equation:
(x + 1)1/2 = (x - 1)1/3
I think the trick is to get to integer exponents. Try raising each side to the 6th power. This means multiply exponents:
So we then have:
(x + 1)3 = (x - 1)2
Expand:
x3 + 3x2 + 3x + 1 = x2 - 2x + 1
Collect terms:
x3 + 2x2 + 5x = 0
Factor:
x (x2 + 2x + 5) = 0
There is only one real solution at x = 0.

Mark H.
So....what should it look like? If you were looking for cube root, I would avoid the notation with the 3 in front of the radical. Instead, use fractional exponents. Thus, you might have: (x + 1)^(1/2) = (x - 1)^(1/3)07/02/19
Alyssa R.
Yes that's the equation I mean to use along with my question07/02/19

Mark H.
I updated my answer based on the revised question07/02/19
Alyssa R.
I tried to make the 3 the index of the second expression, sorry for the confusion.07/01/19