Find an equation in slope intercept form, for the line that is perpendicular to the line

Question

6x+3y=4 and passes through the point (6,-1)

Answer 1

6x + 3y = 4 transforms into y = -2x + 4/3 which has a slope of -2

The perpendicular line has slope +1/2, So, the equation of the line that is perpendicular passing thru (6,-1) is

y + 1 = 1/2(x-6) = x/2 - 3 or y = x/2 - 4