find three consecutive

Question

such that five times the third, minus two times the first, is the same as four times the second, minus forty,

then,

1. write the equation using unknowns

2. solve the equation to find the intergers

Answer 1

Let it be x, x+1, x+2

5(x+2) -2x = 4(x+1)- 40

5x +10 - 2x = 4x + 4 - 40

10 - 4 + 40 = 4x -5x + 2x

46 = x

 

Three consecutive integers are 46, 47, 48.

Answer 2

x, x+1, and x+2 are the integers

5(x+2)-2x=4(x+1)-40

5x+10-2x=4x+4-40

3x+10=4x-36

4x-3x=36+10

x=46

x+1=47

x+2=48