
Terry F. answered 06/16/19
PhD, MBA, MA(math) Math, Statistics, Economics,Finance, Physics, Comp.
Pr ( x < 144 ) = Pr [ z = ( 144 - 170 ) / 15 = - 1.733 ] = from normal table .0415
Melissa D.
asked 06/16/19At a customer service call center for a large company, the number of calls received per hour is normally distributed with a mean of 170 calls and a standard deviation of 15 calls. What is the probability that during a given hour of the day there will be less than 144 calls, to the nearest thousandth?
Terry F. answered 06/16/19
PhD, MBA, MA(math) Math, Statistics, Economics,Finance, Physics, Comp.
Pr ( x < 144 ) = Pr [ z = ( 144 - 170 ) / 15 = - 1.733 ] = from normal table .0415
First of all, 144 is almost 2 standard deviations out so that the answer will be close to 5%.
Actually z=-1.73 and the answer is .5-.4582=.0418.
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