If y varies inversely as x, and y=32 when x=6, what is y when x=8

Answer 1

y=k/x y varies inversely as x and k is any constant

to determine k we know that when x=6 y=32 so 32=k/6 solving for k gives k=192

now we have y=192/x when x=8 y=192/8=24

Hope this helps Danielle

Jim