How do you use the point ( − 7 , -2 ) on the terminal side of the angle to evaluate the six trigonometric functions?

Answer 1

x = -7

y = -2

r = √(x²+y²) = √((-7)²+(-2)²) = √(49+4) = √(53)

sin(Θ) = y/r = -2/√(53)

cos(Θ) = x/r = -7/√(53)

tan(Θ) = y/x = 2/7

csc(Θ) = r/y = -√(53)/2

sec(Θ) = r/x = -√(53)/7

cot(Θ) = x/y = 7/2