The length of a rectangle is 7 more than twice the width, and the area of the rectangle is 99^2yd . Find the dimensions of the rectangle.

Answer 1

x(2x+7) = 99

2x^2 + 7x - 99 = 0

( 2x - 11 )( x + 9 ) = 0

x = 11/2 , x = -9 <--- disqualified

11/2=5 and 1/2 by 18