write the point-slope form of the equation of the line described. Problem: through (4,3), parallel to y= x+2

Question

Help I have no idea how to do this and I really need help with my homework :(

Answer 1

Use a general point slope equation: (y-k)/(x-h)=m or y-k=m(x-h) m is the slope =1, the coefficient of the x term in the given equation. (h,k) is the point on the line, given as (4,3) plug those values into the point slope equation and you get (y-3)/(x-4)=1 Simplify to get y-3 = x-4 or y=x-1 It's parallel because it has the same slope m=1. It runs through the point (4,3) because 3=4-1, substituting into y=x-1. It's a parallel line but with a y-intercept of -1, while the original equation has a y-intercept of 2. It's the original line shifted downward by 3 units. 2-(-1)=3, the difference in the y-intercepts. The final answer is y=x-1

Answer 2

Kimberly,

To be parallel to y=x+2 our line must have the same slope so m=1 and it has to satisfy y-3=x-4 solving for y gives y=x-1.

Regards

Jim