if f(11)=11 and f(n+3)=(f(n)-1)/(f(n)+1) then whats the value of f(2003)

Answer 1

This reiterative formula is a repeating formula with some similar results as follows:

f(11) = 11 f(26) = 11

f(14) = .8333 f(29) = .8333

f(17) = -.0909 f(32) = -.0909

f(20) = -1.2 f(35) = -1.2

f(23) = 11 f(38) = 11 and so on repeating on a n = 12 repeat interval

Counting out to f(2003) it is on the f(11) interval, so f(2003) = 11