Let A(t) = amount in the account after t years. Since interest is compounded continuously, A(t) = Pert, where P is the initial investment amount and r is the interest rate expressed in decimal form.
So, in this problem, A(t) = 1500e0.05t.
The balance reaches 2500 when A(t) = 2500.
We have: 2500 = 1500e0.05t
Divide by 1500 to get 5/3 = e0.05t.
Take natural log of both sides to obtain ln(5/3) = lne0.05t.
Since lnex = x, ln(5/3) = 0.05t
So, t = ln(5/3)/(0.05) ≈ 10.2 years.