Calling base class overridden function from base class method?

Question

public class A {  public void f1(String str) {   System.out.println("A.f1(String)");   this.f1(1, str);  }    public void f1(int i, String str) {   System.out.println("A.f1(int, String)");  } } public class B extends A {  @Override  public void f1(String str) {   System.out.println("B.f1(String)");   super.f1(str);  }  @Override  public void f1(int i, String str) {   System.out.println("B.f1(int, String)");   super.f1(i, str);  } } public class Main {  public static void main(String[] args) {   B b = new B();   b.f1("Hello");  } }I'm seeking that this code would output: B.f1(String) A.f1(String) A.f1(int, String)Yet I'm getting: B.f1(String) A.f1(String) B.f1(int, String) A.f1(int, String)I understand that under the context of B "this" in A.f1(String) is B's instance.Do I have the option to do the chain new B1().f1(String) -> (A's) f1(String) -> (A's) f1(int, String) ? This is a theoretical question, practically the solution would obviously be in A to implement a private function that both f1(String) and f1(int, String) would call.Thank you, Maxim.

Answer 1

Just go ahead and use the super