find the coordinate of the vertex of the following parabola algebraically Y=-4x^2-20

Answer 1

Hi Vishala,

Quadratic functions (where the largest exponent is x²) usually look like ax² + bx + c, where a,b,c are the numbers/coefficients in front of each term.

In this problem, a = -4, b = 0, c = -20.

When looking for the vertex we first find the x-coordinate. The formula for this is -b / 2a = - (0) / 2(-4) = 0. So the x-coordinate of the vertex is 0.

To find the y-coordinate, we plug the x = 0 into the equation given: y = -4(0) - 20 = -20.

The vertex is (0, -20).

Please let me know if I can be more helpful, thanks!

Joe