Hi Mi,
there is a form of the quadratic that we can use when we know the vertex
y = A(x -h)2 +k (where h and k are the values of the vertex
so lets sub -6 and -1 for h and k
y =A(x + 6)2 -1
and now we can find A using one of the roots
when x is -9 or -3 y =0
0 = A(-3 + 6)2 -1
1 = A(3)3
1 = 9A
1/9 = A
the final equation is
y = (1/9)(x + 6)2 -1
Hope this helps