Write a quadratic function in vertex form whose graph has the vertex (1,2) and passes through the point (3,10)

Answer 1

The general equation is: y = a(x - h)² + k

With vertex at (h,k) = (1,2), we have: y = a(x - 1)² + 2

To solve for a, substitute the given point (x,y) = (3,10) into the equation.

10 = a(3 - 1)² + 2

8 = a(2)²

8 = a(4)

2 = a

Now, for a final answer, we have: y = 2(x - 1)² + 2