Question 4 A line passes through the point(5,7) and has a slope of 4 . Write an equation for this line.

Answer 1

We can use the point-slope form of the equation of a line, which is:

y - y1 = m(x - x1)

where m is the slope of the line, and (x1, y1) is a point on the line.

Substituting the given values, we get:

y - 7 = 4(x - 5)

Expanding the right-hand side, we get:

y - 7 = 4x - 20

Adding 7 to both sides, we get:

y = 4x - 13

So the equation of the line passing through the point (5,7) with a slope of 4 is y = 4x - 13.

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Answer 2

Use the "slope-offset" format: y = m*x + b

m is the slope

b is the y offset---i.e. the value of y if x = 0

Simply plug the given values for x and y and m into the equation to get:

7 = 4*5 + b

solve to get b = -13

SO: y = 4*x - 13

Answer 3

In slope intercept form you are looking for the line

y= mx + b

m is the Slope

m = 4

Now just plug in the coordinates (5, 7) from above to solve for b

7 = 4(5) + b

7 = 20 + b

Subtract 20 from both sides of the equation

7- 20 = b

-13 = b

The line in slope intercept form is

y = 4x -13

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