Catch multiple exceptions in one line (except block)?

Question

I know that I can do: try: # do something that may fail except: # do this if ANYTHING goes wrongI can also do this: try: # do something that may fail except IDontLikeYouException: # say please except YouAreTooShortException: # stand on a ladderBut if I want to do the same thing inside two different exceptions, the best I can think of right now is to do this: try: # do something that may fail except IDontLikeYouException: # say please except YouAreBeingMeanException: # say pleaseIs there any way that I can do something like this (since the action to take in both exceptions is to `say please`): try: # do something that may fail except IDontLikeYouException, YouAreBeingMeanException: # say pleaseNow this really won't work, as it matches the syntax for: try: # do something that may fail except Exception, e: # say pleaseSo, my effort to catch the two distinct exceptions doesn't exactly come through.Is there a way to do this?

Answer 1

A good place to begin with any question about Python syntax is the Python documentation available at docs.python.org. So let's see what the documentation has to say:

A try statement may have more than one except clause, to specify handlers for different exceptions. At most one handler will be executed. Handlers only handle exceptions that occur in the corresponding try clause, not in other handlers of the same try statement. An except clause may name multiple exceptions as a parenthesized tuple...

The key here is the last line that mentions naming multiple exceptions as a parenthesized tuple. To achieve the behavior you are looking for, the exceptions need to be place into a tuple:

(IDontLikeYouException, YouAreBeingMenException)

With that in mind, the entire try/except block should look something like this:

try:

something_that_may_fail()

except (IDontLikeYouException, YouAreBeingMeanException) as ex:

say_please()