What Celsius temperature, T2, is required to change the volume of the gas sample in Part A (T1 = 33 ∘C , V1= 1.36×103 L ) to a volume of 2.72×103 L ?

Question

Assume no change in pressure or the amount of gas in the balloon.

Answer 1

Simply put, you are asking what temperature should a gas be heated to in order to double its volume..Temoerature one is 33^OC, and starting volume is 1.36 x 10³L; final volume is 2.72 x 10³L, which is exactly double the initial volume. therefore, the temperature,T₁, should be multiplied by the ratio of temperatures:

T2 = T1 x 2.72/1.36 = 33^OC x 2 = 66^OC