At a concession stand, one person purchased 3 drinks and 3 soft pretzels for a total of $9.00. Another person purchased 4 drinks and 2 soft pretzels for a total of $8.50. Whats the price of one drink?

Answer 1

d: drinks and p: pretzels and solve with elimination

(3d + 3p = 9.00)(2)

(4d + 2p = 8.50)(-3)

6d + 6p = 18.00

-12d + -6p = -25.50

-6d = -7.5

d = $1.25

Drinks cost $1.25 each.

In case you would need to find the cost of pretzels too, here is the solution

Plug d into origional equation and solve for p

3(1.25) + 3p = 9.00

p = $1.75

Answer 2

We have two equations in two unknowns, namely

3 x D + 3 x P = 9.00 and

4 x D + 2 x P = 8.50 Wecan solve by elimination

6 x D + 6 x P = 18.00 and

-12 x D - 6 x P = -25.50 Adding these equations yields:

6 x D = -7.50 So D = 1.25