The perimeter of a rectangle is 12 inches and its area is 8 square inches. What are its​ dimensions?

Answer 1

p = 2l + 2w = 12

A = lw = 8

l = 8/w

Substitute:

2(8/w) + 2w = 12

16/w + 2w = 12

16 + 2w^2 = 12w

2w^2 - 12w + 16 = 0

(2w - 4)(w - 4) = 0

w = 4

w = 2

If w = 4, then l = 2 ( this makes no sense because l exceeds w by definition.)

If w = 2, then l = 4

So, technically there are two solutions, but, length should exceed width...