Patricia J. answered 05/07/19
Experienced Tutor specializing in Math, ELA and Test Prep
-4.9t2+40t+4=2
applying the quadratic formula, move 2 over and set the equation equal to 0 to get
-4.9t2 +40t+4-2=0 or simplified,
=-4.9t2 + 40t + 2 =0 x1=(-40)±√402+39.2 x1= (-40)±√1639.2 -40±40.487
=(-4.9) + 40t + 2= 0 2((-4.9) -9.8 -9.8
a=--4.9 b= 40 c= 2
x1 =(-40) ¯±√402-4(-4.9)(2) x1=(-40)±√1600+39.2 x1=0.487
2(-4.9) -9.8 -9.8 or - 0.05 first solution
second solution:
x2=-40-40.487
-9.8
=--80.487
-9.8 divide and you get 8.218 so x1=-0.05 and x2= 80.487
