The domain of f-1(x) is the range of f(x).
Since √(x+5) ≥ 0, the range of f(x) = √(x+5) + 2 is [2, ∞).
So, the domain of f-1(x) is [2, ∞).
The domain of f-1(x) is the range of f(x).
Since √(x+5) ≥ 0, the range of f(x) = √(x+5) + 2 is [2, ∞).
So, the domain of f-1(x) is [2, ∞).
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