What is the missing constant term in the perfect square that starts with x^2+14x

Answer 1

Tiffany,

heres how you can discover the principle:

if if someone gave you the perfect square

(x + b)(x + b), and you multiplied it out, you would have

x² + 2bx + b²

You are missing the constant term, so you are facing

x² + 2bx

This means that

2bx = 14x

From that fact, you can find b and from there, the constant term b².

Answer 2

We need to find something that looks like (x + a constant) that we can multiply by itself to x^2 + 14x + a constant. Let's start by taking (x+c) and squaring it to see what happens:

x + c

1. (x + c)

cx + c²

x² + cx

x² +2cx + c²

So, we can see that we want our x²+14x + k to be the same as x² + 2cx + c²

which means that 2cx = 14x.

Dividing both sides by 2, we get cx= 7x, which means that c = 7.

We can now substitute 7 for c, and we get as follows:

(x+7)² = x² + 14x + 49,

So the missing constant term in the perfect square that starts with x²+14x is 49.

Answer 3

1. Use the following formula to find the missing constant term...

(b/2)²

1. b is the middle term so in this case it is 14, so we just plug that into our formula

(14/2)²

14/2 = 7

7² = 49

The missing constant term for the given perfect square equation is 49.

If you have any other questions or questions regarding this topic, please let me know. Thanks.