Inactive Tutor answered 04/30/19
Tutor
New to Wyzant
Distribute just like you would if the "i" was an x: 6*1+6*i-2i*1-2i*i = 6+6i-2i-2i2 = 4i+6-2i2.
Then remember that i2=-1: 4i+6-2*-1 = 4i+6+2 = 4i+8.
Lucy S.
asked 04/30/19Inactive Tutor answered 04/30/19
Distribute just like you would if the "i" was an x: 6*1+6*i-2i*1-2i*i = 6+6i-2i-2i2 = 4i+6-2i2.
Then remember that i2=-1: 4i+6-2*-1 = 4i+6+2 = 4i+8.
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