find the point slope equation for the line that passes through the points (-8,-32) and (3,1) use the first point in your equation

Answer 1

We want y = mx + b first to get m and b for the Point Slope form

We can calculate m with the points given since

m = (y₂ - y₁)/(x₂ - x₁)

m = (1 -(-32))/(3 - (-8))

m = (1 + 32)/(3 + 8)

m= 33/11

m =3

Next we plug the first point (-8 ,-32) in to y = mx + b to solve for b

-32 = 3(-8) + b

-32 = -24 + b

Add 24 to both sides of the equation to give

-32 + 24 = b

-8 = b

So

y = mx + b

is

y = 3x -8

Checking if we plug in 3 for x we get

y = 3(3) - 8

y = 9 - 8

y = 1

Which is the other point (3, 1)

You can convert y = mx + b the Slope Intercept form to the Point Slope form by subtracting 3x from both sides of the equation to give

-3x + y = -8 is the Point Slope Form

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