An object is dropped from 44 feet below the tip of a pinnacle atop a 368 foot building the height h of the object after t sec is given 6t squared + 324. find how many seconds before it reaches ground

Question

object is dropped from 44 feet below the tip of a pinnacle atop a 368 foot building the height h of the object after t seconds is given by the equation h equals -16t squared + 324. find how many seconds passed before the object reaches the ground

Answer 1

Set your height equation, -16T²+324 equal to 0, as 0 is ground level

Solve for T, T²=324/16=81/4, T=9/2=4.5

T= 4.5 seconds