Christopher R. answered 12/02/14
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Nick, since the y-coordinates of the vertices and foci are the same indicates this is a horizontal hyperbola. The equation of the hyperbola is in the form:
(x-h)^2/a^2-(y-k)^2/b^2=1
The distance between the vertices is 2a=11-9=2
2a=2 Divide both sides of the equation by 2. This implies a=1
The center of the hyperbola is ((9+11)/2,(1+1)/2)=(20/2,2/2)=(10,1) This implies h=10 and k=1.
Find the distance from the center to the foci in which is c=12-10=2
Determine b^2 from the equation c^2=a^2+b^2
b^2=c^2-a^2=2^2-1^2=4-1=3
Substitute these into the hyperbola equation in which gives its equation based upon the given conditions stated in the problem.
(x-10)^2/1-(y-1)^2/3=1