The length of a rectangle is three yards longer than it's width. If the perimeter of the rectangle is 34 yards, find its area

Question

The length of a rectangle is three yards longer than it's width. If the perimeter of the rectangle is 34 yards, find its area

Answer 1

This is a relatively straightforward application of solving with substitution.

We know that l = w + 3. We also know that l * w = area and that 2*l + 2*w= 34.

If we substitute w + 3 for l in the perimeter equation, we find that 2* (w+3) + 2*w) = 34. Therefore 2w+6+2w = 34 and 4w = 28. Therefore w = 7 and l = w+3 = 10. Area = l * w = 7 * 10 = 70 yards².