How many gallons of a 60​% antifreeze solution must be mixed with 80 gallons of 10​% antifreeze to get a mixture that is 50​% ​antifreeze? Use the​ six-step method.

Answer 1

X60 + 80(10) = (X+80)50

60x + 800 = 50x + 4000

10x = 3200

x = 320 gallons of 60% needed to mix with 80 of 10% to get 400 of 50%

10 is within 40 of 50

60 is within 10 of 50

that's a 4 to 1 ratio

you need 4 times as much 60 as of 10

4 x 60 = 320