
Mark M. answered 04/17/19
Mathematics Teacher - NCLB Highly Qualified
90 = -16t2 + 80t
90 = -16(t2 - 5t)
90 = -16(t2 - 5t + (-2.5)2) + 100
-10 = -16(t - 2.5)2
0.625 = (t - 2.5)2
±√0.625 = t - 2.5
2.5 ± √0.625 = t
Zenphonie F.
asked 04/17/19What time would it be reached?
Mark M. answered 04/17/19
Mathematics Teacher - NCLB Highly Qualified
90 = -16t2 + 80t
90 = -16(t2 - 5t)
90 = -16(t2 - 5t + (-2.5)2) + 100
-10 = -16(t - 2.5)2
0.625 = (t - 2.5)2
±√0.625 = t - 2.5
2.5 ± √0.625 = t
Yes, at t = 5/2 the ht will be 100 ft.(Set the derivative= 0)±
At t=(10±√10)/4 seconds (Solve the quadratic) It reaches 90 ft going up and coming down!
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