Hi Madison,
Let x = cost of small boxes
Let y = cost of large boxes
3x + 9y = 162 (3 small, 9 large = $162
9x + 11y = 246 (9 small, 11 large = $246
now solve by eliminating one of the variables
multiply first equation by 3, doing this so I will have 9x and I can then subtract and get rid of the x variable
9x + 27y = 486 (multiplied first equation by 3
9x + 11y = 246
now subtract and you get
16y = 240
or y = 15
now use this back in the original first equation and solve for x
3x + 9(15) = 162
3x + 135 = 162
3x = 27
x = 9
Hope this helps