Arithmetic sequence

Question

Find the 14th term of the arithmetic sequence whose common difference is d=6 and whose first term is a^1=2

Answer 1

an = a1 +d(n-1) = 2 +6(n-1) = 6n-4

a14 = 6(14)-4 = 84-4 = 80 = 14th term of the AP

2,8,14, 20,26 = a1 through a5

32,38,44,50,56 = a6 through a10

62, 68,74,= a11 through a13,

80=14th term