1,4,9,16,25… ..n=10

Daisy,

∑

_{1}^{N}n^{2}=(1/6)N(N+1)(2N+1) =385 for N=10Regards

Jim

1,4,9,16,25… ..n=10

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Fairport, NY

Daisy,

∑_{1}^{N} n^{2} =(1/6)N(N+1)(2N+1) =385 for N=10

Regards

Jim

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- Sum 45
- Arithmetic 46
- Arithmetic Series 18
- Geometric Sequence 42
- Arithmetic Problems 36
- Term 15
- Sequences 91
- Terms 12
- Arithmetic Progression 14
- Common Difference 9

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