N(t)= 300 No =1000. N(t)/No= 300/1000=.3 and t 1/2 (half life) = 5730(-ln2)(t)/5739
.3 = e^(-ln2)(t)/5730. If we now take the natural log of both sides we gert
ln3 = (-ln2)(t)/5730
(5730)(ln3)= (-ln2)t
t= (5730)(ln3)/(-ln2). put this in your calculator and you get
t=9952.8
Remember when you take the natural log (ln) of e raised to some power the answer is whatever power e is raised to. This technique is needed to solve these sorts of equations
I hope this helps. The numbers are ugly but the principal is simple