Write a polynomial function of least degree with integral coefficents that has given zeros ¾, -3, -2/5?
Since the polynomial function will have three roots, we can expect the answer to be a cubic equation.
Here's how to find the cubic polynomial..
If (4x - 3) is a factor of the cubic equation, then x = 3/4 will be a zero (root).
If (x + 3) is a factor of the cubic equation, then x = -3 will be a zero (root).
If (5x + 2) is a factor of the cubic equation, then x = -2/5 will be a zero (root).
All that is left is to multiply the three factors to obtain a cubic polynomial with the desired roots.
Tackling the more difficult multiplication first, (4x - 3)(5x + 2) = 20x2 + 8x - 15x - 6 = 20x2 - 7x - 6.
Now multiplying that quadratic by (X + 3),
(X + 3)(20x2 - 7x - 6) = 20x3 -7x2 - 6x + 60x2 - 21x - 18.
Combining like terms, it simplifies to 20x3 + 53x2 - 27x - 19. Since the coefficients have not factors in common, it is lowest terms.
So the final solution is 20x3 + 53x2 - 27x - 19 = 0.