Francisco P. answered 11/26/14
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Rigorous Physics Tutoring
x2 - 2x - 35 = y [1]
x = y - 5 [2]
x = y - 5 [2]
Solve for y in [2]: y = x + 5
Substitute in [1]: x2 - 2x - 35 = x + 5
Solve for x by factoring: x2 - 3x - 40 = 0
(x + 5)(x - 8) = 0
x = -5 or 8.
Solve for y using [2]: If x = -5, then y = 0.
If x = 8, y = 13.
The solution set is {(-5, 0), (8, 13)}.