Denise G. answered 04/03/19
Algebra, College Algebra, Prealgebra, Precalculus, GED, ASVAB Tutor
The key to starting off factoring polynomials is:
Factors of p (coefficient)/factors of q (leading coefficient)
For this problem that would be (factors of 12)/(factors of 1)
This would be (+/-1, +/-2, +/-3, +/-4, +/-6, +/-12)
From here it is a manner of testing each of these by synthetic division. You find that -2 works for a zero. So the factor that gives you this is (x+2)
The results of synthetic division are x2-5x-6. This can be factored to give the remaining 2 factors.
x2-5x-6 = (x-6)(x+1)
So the finished factorization is (x+2)(x-6)(x+1)
To graph this: https://www.desmos.com/calculator