Patrick B. answered 03/31/19
Math and computer tutor/teacher
20000 = P * e^(0.06*12) =
20000 = P * e^0.72
20000/ e^0.72 = P
9735.05 = P
Maverick M.
asked 03/31/19
Patrick B. answered 03/31/19
Math and computer tutor/teacher
20000 = P * e^(0.06*12) =
20000 = P * e^0.72
20000/ e^0.72 = P
9735.05 = P
Cara Marie M. answered 03/31/19
Versatile Tutor in the Maths, Sciences with a PhD in Biochemistry
The amount after 12 years (A) is equal to the the amount you start with (Ao) times ert, where r = interest rate and t = time in years.
A = Ao e^rt = (20,000)*e(.06*12) = 20,000e.72 = 41,088.66
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