Heather P. answered 03/28/19
Certified Tutor with 19 Years Teaching & Tutoring Algebra 2 Topics
The number of unknowns tells you how many equations you mush have. For this problem, I recommend one equation for assembly, one for testing, and one for packaging. First, decide which variables you'll use, and then define what they represent. (I chose a=# of 40" tvs, b=# of 46" tvs, c=# of 52" tvs). Since assembly requires 0.75 hrs for the 40", 1 hr for the 46", and 1.5 hrs for the 52", the assembly equation should be .75a+1b+1.5c=17.75. The other 2 equations will be similar.
Once you have all 3 equations, you must go thru the process of solving for each variable. You can use matrices if you're familiar with the process. But if not, you start by eliminating a variable from 1 PAIR of equations, then eliminate the SAME variable from a DIFFERENT pair of equations. Then you can use your 2 new, 2 variable equations to solve for one variable, using either elimination or substitution. Then just go in reverse... take the value you got on the last step, and substitute it back in to one of your 2 variable equations to find the value of another variable. Then take both values and substitute them back in to one of your original equations to find the 3rd value.
Be sure to check your solution by substituting ALL 3 values into ALL 3 original equations to see if they work. If they do, your solution is correct.
Please let me know if you need further assistance.