
Dal J. answered 11/22/14
Tutor
4.9
(64)
Expert Instructor in Complex Subjects and Public Speaking
Okay, let's take t as the number of nine dollar increments we'll raise the rent, R as the price of Rent, and N as the number of apartments that will be rented.
we know that the number of apartments that will rent is 100 minus t, and we know that the price is 396 plus 9*t, and the total income is the product of those two numbers
N(t) = (100 - t)
R(t) = (396+9t)
$(t) = (100 - t)(396+9t)
$(t) = 39600 +900t - 396t -9t^2
$(t) = -9t^2 + 504t + 39600
Depending on what kind of class you are in, you could either use the quadratic equation to find the two zeros of this equation and the best rent will be halfway between, or you could take the derivative and find the zero of that.
It's calculus, so we'll do the derivative.
$'(t) = -18t + 504
t = 504/18 = 28
so the proper rent is
R(28) = (396+9*28) = 648