values of x

Question

The approximate value of x that are solution to f(x)=0 where f(x) 0= -6x^2+4x+3

Answer 1

Shawna, I would use the quadratic formula to solve for x.

 

x=(-4±√(4^2-4(-6)(3)))/(2*-6)=(-4±√(16+72)))/-12=(-4±√88)/-12

 

x=(-4+√88)/-12≅-0.448 and x=(-4-√88)/(-12)≅1.115

 

Hope this helps.