Denise G. answered 03/19/19
Algebra, College Algebra, Prealgebra, Precalculus, GED, ASVAB Tutor
The first step is to express the zeros as factors. This is
(x-1)(x-2)(x-4)
Then you multiply these expressions together
(x^2-3x+2)(x-4) when I multiply the first 2 terms by FOIL
Then if I use the distributive property for the next multiplication I get:
x^2(x-4)-3x(x-4)+2(x-4)
Using the distributive property again
x^3-4x^2-4x^2+12x+2x-8
Combining like terms:
x^3-7x^2+14x-8