The general rule is
x3-y3=(x-y)(x2+xy+y2)
Rearrange a3-(1/a3) to be (a)3-(1/a)3
Then x=a and y=1/a in the general rule
(a-1/a)(a2+(a)(1/a)+(1/a2))
Since (a-1/a)=3
3(a2+1+(1/a2))
Surd A.
asked 03/18/19If [a - 1/a ] = 3 then a^3 - 1/a^3 = ?
The general rule is
x3-y3=(x-y)(x2+xy+y2)
Rearrange a3-(1/a3) to be (a)3-(1/a)3
Then x=a and y=1/a in the general rule
(a-1/a)(a2+(a)(1/a)+(1/a2))
Since (a-1/a)=3
3(a2+1+(1/a2))
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