Francisco P. answered 11/16/14
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Rigorous Physics Tutoring
Starting binomial: x2 + (4/7)x
Complete the square with a = 1, b = 4/7, and c = 0:
Take half of b: b/2 = 2/7
Square b/2: (b/2)2 = (2/7)2 = 4/49
Add and subtract (b/2)2: x2 + (4/7) x + (2/7)2 - (2/7)2
1st 3 terms form a square trinomial: [x2 + (4/7) x + (2/7)2] - (2/7)2
Rewriting the trinomial as a square: (x + 2/7)2 - (2/7)2
Factor the difference of squares:
[(x + 2/7) + 2/7][(x + 2/7) - 2/7]