its just dificult
its just dificult
Juniper...let me add a small element you should know, when it comes to solving problems with a coefficient and a variable(I'm assuming you know what these terms are...). Rule/Skill 1: when solving the power of an expression(finding the square...cubed...root...etc) of an expression...separate the expression into the constants(values you know) and the variables(values you don't know), in your case. /49x^6 basically the square root of the expression 49 x to the 6th power. This is the same as 49 times x to the 6th power and can be written like this /(49) x /(x^6) in this case...I'm using / to represent square root. I'm sure you already know, the square root of 49 is /49 = 7, that's for the knowns. Now, for the unknowns /x^6 which in words is the square root of x to the 6th power. So (some value x) times (some value x) equals x^6. As it turns out, as explained above (x^3) times (x^3) equals x^6 or (x^3)(x^3) = x^6. Finally; /49x^6 = 7x^3 Hope that helps...good luck
In real domain,
sqrt(49x^6) = 7|x^3|
Attn: 7x^3 is incorrect since in real domain sqrt(49x^6) is larger than or equal to 0 even if x < 0.
When you enter a question, there is an option in the icon menu to create an exponent... the one marked x^{2}.
You can write 49 x^6 or 49x^{6}. The latter might be better since it looks just like what you're seeing in a textbook.
The symbol ^ is called a hat and it is used to indicate an exponent....such as in your question is would look like "What is the square root of 49x^6.....the answer is 7x^3....depending on your teacher the x^3 should be in absolute value symbols because you took the even root of an even exponent and its result was an odd exponent.
Comments
Thank you and yes i understand those terms lol (: im just having difficulty because i blew off the beginning of this year. And now this is my last chance to even try and understand Algebra 2. But thank you this was really helpful.