help

help

Tutors, please sign in to answer this question.

Daniela,

Break the problem into two different multiplication problems:

(x^{4}+11x^{3}+33x^{2}+24x+32) * x and (x^{4}+11x^{3}+33x^{2}+24x+32) * 6

multiplying by x is easy, just increase the power of each member of the polynomial. Arrange the two polynomials underneath each other to make addition of like terms easier.

(x^{4}+11x^{3}+33x^{2}+24x+32) * x = x^{5 }+ 11x^{4 }+ 33x^{3 }+ 24x^{2 }+ 32x

(x^{4}+11x^{3}+33x^{2}+24x+32) * x = 6x^{4 }+ 66x^{3 }+198x^{2 }+144x + 192

(x^{4}+11x^{3}+33x^{2}+24x+32)(x+6) = x^{5} + (11+6)x^{4} + (33+66)x^{3} + (24+198)x^{2} + (32+144)x +192

Complete the addition and you'll have your answer!

Amaan M.

Former High School Math and Economics Teacher

New York, NY

5.0
(54 ratings)

David T.

Very Experienced, Knowledgeable, and Patient Math Tutor

Dobbs Ferry, NY

5.0
(93 ratings)

Adam P.

Highly Experienced Test Prep Instructor

Brooklyn, NY

4.9
(80 ratings)