If a and b are mutually exclusive events with p(A) =0.3 ,p(B)= 0.5 ,then p(AUB) is equal to what ?

Answer 1

We know that p(A union B)=p(A)+p(B)-p(A intersection B) and since A, B are mutually exclusive p(A intersection B)=0. Thus, p(A union B)=p(A)+p(B)=0,3+0,5=0,8.