What is maximum possible profit?

Question

The profit for a product can be described by the function p(x)=202x-5000-x^2 where x is the number of units produced and sold. To maximize profit, how many units must be produced and solid? What is the maximum possible profit?

Answer 1

Hello Brineicia

If you have not yet solved this problem, here is the solution. First of all, you have to find the x-value of the vertex, i.e., -b/2a = -202/-2 = 101 units sold. Then you plug 101 back into the function, i.e.,

-(101)² + (202)(101) - 5000 = -10,201 + 20,402 - 5000 = $5,201.00 (maximum profit). Therefore, you have to sell 101 units to maximize profit.

Sincerely

Michael I.